Pretty straight forward, acceleration on earth is about 9.8, so in 1 second it went from 0 m/s to 9.8 m/s resulting in an average speed of 4.9 over 1 second, whcih is what you are given, following the same logic, at 3 sec it will go at 9.8*3=29.4 starting at 0m/s at 0 seconds for an average speed of 14.7m/s over 3 seconds, for a total of 44.1 meters, So if it did 4.9m in 1 sec and 44.1 in 3 sec it means it did 39.2m in the last 2 secs, so if rounded it gives you C.

Was this answer helpful? Yes | No

ur a nob

Was this answer helpful? Yes | No

If the suppository doesn`t work, try an enema.

Was this answer helpful? Yes | No

I have no idea what equation to use on the problem.

Was this answer helpful? Yes | No

3.03sec

Was this answer helpful? Yes | No

Use D=Vo(t) .5(a)(t)^2 D is what your finding out Vo=Initial Veolocity= 0m/s t=how long the ball is in the air , 3s a=acceleration, -9.80m/s^2 Find the answer for the 3s as t D=(0m/s)(3s) .5(-9.80m/s^2)(3s)^2 So D= -40.5m after 3 sec (Because it is falling down, so its negative) Then take -40.5m - (-4.9m) = -35.6m!!

Was this answer helpful? Yes | No

4s

Was this answer helpful? Yes | No

terminal velocity- look it up

Was this answer helpful? Yes | No

students in chuck stone`s lab measure the speed of a steel ball to be 8.0 m/s when launched horizontally from a 1.0-m high tabletop. Their objective is to place a 20-cm tall coffee can on the floor to catch the ball. Show that they score a bull`s eye when the can is placed 3.2 m from the base of the table

Was this answer helpful? Yes | No

A 60 kg box is pushed horizontally across the floor a distance of 20 meters. The force required is 15 N. In this effort, ______ joules of work is done.

Was this answer helpful? Yes | No